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wasmtime/meta/constant_hash.py
Jakob Stoklund Olesen f1e2dffa81 PEP8 formatting.
2016-05-12 13:37:03 -07:00

80 lines
1.9 KiB
Python

"""
Generate constant hash tables.
The `constant_hash` module can generate constant pre-populated hash tables. We
don't attempt parfect hashing, but simply generate an open addressed
quadratically probed hash table.
"""
def simple_hash(s):
"""
Compute a primitive hash of a string.
Example:
>>> hex(simple_hash("Hello"))
'0x2fa70c01'
>>> hex(simple_hash("world"))
'0x5b0c31d5'
"""
h = 5381
for c in s:
h = ((h ^ ord(c)) + ((h >> 6) + (h << 26))) & 0xffffffff
return h
def next_power_of_two(x):
"""
Compute the next power of two that is greater than `x`:
>>> next_power_of_two(0)
1
>>> next_power_of_two(1)
2
>>> next_power_of_two(2)
4
>>> next_power_of_two(3)
4
>>> next_power_of_two(4)
8
"""
s = 1
while x & (x + 1) != 0:
x |= x >> s
s *= 2
return x + 1
def compute_quadratic(items, hash_function):
"""
Compute an open addressed, quadratically probed hash table containing
`items`. The returned table is a list containing the elements of the
iterable `items` and `None` in unused slots.
:param items: Iterable set of items to place in hash table.
:param hash_function: Hash function which takes an item and returns a
number.
Simple example (see hash values above, they collide on slot 1):
>>> compute_quadratic(['Hello', 'world'], simple_hash)
[None, 'Hello', 'world', None]
"""
items = list(items)
# Table size must be a power of two. Aim for >20% unused slots.
size = next_power_of_two(int(1.20*len(items)))
table = [None] * size
for i in items:
h = hash_function(i) % size
s = 0
while table[h] is not None:
s += 1
h = (h + s) % size
table[h] = i
return table
if __name__ == "__main__":
import doctest
doctest.testmod()