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Always delete previous releases, not only for dev (#1001)

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This will delete a same-name of a previous release for all tags, not
just the dev tag. That way if we need to retry a tagged release we'll
delete it and recreate it as usual.

Closes #978
This commit is contained in:
Alex Crichton
2020-02-26 17:09:49 -06:00
committed by GitHub
parent 76e08d60d4
commit ead53b3f23
1 changed files with 13 additions and 16 deletions
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29
.github/actions/github-release/main.js vendored
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@@ -24,24 +24,21 @@ async function runOnce() {
const octokit = new github.GitHub(token); const octokit = new github.GitHub(token);
// If this is a `dev` release then we need to actually delete the previous // Delete the previous release since we can't overwrite one. This may happen
// release since we can't overwrite a new one. We also need to update the // due to retrying an upload or it may happen because we're doing the dev
// `dev` tag while we're at it. So here you'll see: // release.
// const releases = await octokit.paginate("GET /repos/:owner/:repo/releases", { owner, repo });
// * Look for the `dev` release, then delete it if it exists for (const release of releases) {
// * Update the `dev` release to our current sha, or create one if it doesn't if (release.tag_name !== name) {
// exist continue;
if (name == 'dev') {
const releases = await octokit.paginate("GET /repos/:owner/:repo/releases", { owner, repo });
for (const release of releases) {
if (release.tag_name !== 'dev') {
continue;
}
const release_id = release.id;
core.info(`deleting release ${release_id}`);
await octokit.repos.deleteRelease({ owner, repo, release_id });
} }
const release_id = release.id;
core.info(`deleting release ${release_id}`);
await octokit.repos.deleteRelease({ owner, repo, release_id });
}
// We also need to update the `dev` tag while we're at it on the `dev` branch.
if (name == 'dev') {
try { try {
core.info(`updating dev tag`); core.info(`updating dev tag`);
await octokit.git.updateRef({ await octokit.git.updateRef({