No longer store sizes as bitfields

On most (x86) processors, using bitfields is low than using slightly
more memory.
This commit is contained in:
Alexis Engelke
2019-01-13 16:19:41 +01:00
parent 5bdafbbcf0
commit 9d3f34bcc6
2 changed files with 15 additions and 37 deletions

View File

@@ -116,9 +116,9 @@ struct Instr
{
uint16_t type;
struct Operand operands[4];
uint8_t segment : 3;
uint8_t width : 3;
uint8_t addr_size : 2;
uint8_t segment;
uint8_t op_size;
uint8_t addr_size;
/**
* Encoded as 1 << (scale - 1) **or** no scaled register at all if zero.
@@ -137,8 +137,8 @@ struct Instr
typedef struct Instr Instr;
#define INSTR_SEGMENT(instr) ((instr)->segment)
#define INSTR_WIDTH(instr) ((1 << (instr)->width) >> 1)
#define INSTR_ADDRSZ(instr) ((1 << (instr)->addr_size) >> 1)
#define INSTR_WIDTH(instr) ((instr)->op_size)
#define INSTR_ADDRSZ(instr) ((instr)->addr_size)
#define INSTR_HAS_REP(instr) ((instr)->prefixes & PREFIX_REP)
#define INSTR_HAS_REPNZ(instr) ((instr)->prefixes & PREFIX_REPNZ)
#define INSTR_HAS_LOCK(instr) ((instr)->prefixes & PREFIX_LOCK)